ANSWER: The rules you learn like the one to your quotation use just if the fees will likely be regarded as an ongoing liquid that may bequeath in itself out on any facial skin, regardless of how large, and also zero thickness. Without a doubt, a situation as you identify, that have 5 too much electrons is within no way including a fluid and that i do guess that everything from 5-0 to help you 0-5 may be the shipments more than an occasion. The theory is that, the 5 electrons create arrange by themselves to ensure that each was since well away from the other 4 that one may, but around would not be a different sort of including shipments.
QUESTION: Is it you can easily in order to suspend an electron via electrostatic levitation when you look at the a great consistent magnetic profession? And when the fresh voltage is actually reduced Adult datings dating site sufficient therefore the electrostatic force to your electron try lower than the brand new push on account of brand new electron’s weight create the new electron then feel a good ‘fall’ owed to help you the law of gravity?
I am asking this simply because I am wanting to know when the place a good positron when you look at the an excellent consistent magnetized career (into the a vacuum) and you can decreasing the voltage so you can an incredibly quick worthy of so that the fresh electrostatic push is gloomier compared to the pounds create end up in a beneficial positron so you’re able to and additionally experience good ‘fall’. If in case they performed feel a trip it may be ascertained whether it create slip up or downwards.
By inertial mass After all the ratio of your own push your apply at they split up because of the its velocity, this means that the resistance to getting accelerated
I’m 17 yrs . old and also in the uk planning to research physics from the college or university in sep and you may was just interested in learning so it given that our topics in 2010 is electricity phenomena and you can we chatted about millikan’s petroleum miss try hence checked a comparable variety of suspension if the electrostatic push and force because of gravity had been healthy.
Today, we know to over the top reliability the inertial size from a beneficial positron is equal to the fresh new inertial bulk of a keen electron
ANSWER: It is always nice to see young folks asking interesting questions. First, I need to correct one thing: everywhere you refer to a “magnetic field” you should say “electric field”; a magnetic field exerts no force on a charge at rest which is what you want to observe, la Millikan. (A more correct way, relativistically, to say this would be that they have equal momenta for equal speeds.) I believe it is true that nobody has ever “weighed” a positron by measuring the force it experiences in a gravitational field. But, if the gravitational mass were different from the inertial mass, this would fly in the face of the theory of general relativity. But, let’s talk about the feasibility of your experiment. The mass of an electron is about 10 -30 kg so its weight would be about 10 -29 N (taking g?10 m/s 2 ). The electron charge is about 1.6×10 -19 C and so the electric field required to levitate an electron would be 10 -29 /1.6×10 -19 ?6×10 -11 V/m. Suppose we use a parallel plate capacitor to create this field. The charge density ? on a plate with field E is about ?=?0E?10 -11 x6x10 -11 =6×10 -22 C/m 2 which would correspond to an electron density on the plates of about 6×10 -22 /1.6×10 -19 ?0.004 electrons/m 2 ! This would correspond to about one electron for every 250 square meters! That would not give a very uniform field would it? There is no such thing as a uniform surface charge density because charges in nature do not comprise a continuous fluid; so really tiny uniform fields are not possible. I did all that just for the fun of it, but there is an even more serious considerationthe earth itself has an electric field near the surface of typically 100 V/m pointing down, so an electron would be repelled upward. To do your experiment you would have to get rid of that field and I do not believe that it would be possible to be assured that you could make the residual field much less than your 6×10 -11 V/m. Back to the drawing board! Keep asking those hard and interesting questions, though, and good luck with your university studies.